Question

The density of a 3M sodium thiosulphate solution is 1.25 g/cm³. Calculate the molalities of Na+ ans S2O3 2- ions; and mole fraction of sodium thiosulphate.
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Answer 1

The density of a 3 M sodium thiosulphate solution (Na2S2O3) is 1.25 g per mL. Calculate (i) the percentage by weight of sodium thiosulphate (ii) the mole fraction of sodium thiosulphate and (iii) the molalities of Na+ and S2O32- ions.Read more on Sarthaks.com - https://www.sarthaks.com/285106/the-density-of-a-3-m-sodium-thiosulphate-solution-na2s2o3-is-1-25-g-per-ml

Given, molarity of Na2S2O3 = 3 mol/L :. Moles of Na2S2O3 = 3 Thus, weight of Na2S2O3 = 3 x 158 = 474 g and volume ( V) of solution = 1 L = 1000 mL .'. Weight of solvent = 1250 - 474 = 776 g Read more on Sarthaks.com - https://www.sarthaks.com/285106/the-density-of-a-3-m-sodium-thiosulphate-solution-na2s2o3-is-1-25-g-per-ml