Question

the diagonal of a rectangular field is 60 M more than its breadth if its length is 30 more than the breadth find the length and breadth of the field ​

Answer 1

Step-by-step explanation:

Consider a rectangle ABCD

LET AB Be the length and BC be the breadth

AB=30+BC

Now the diagona AC is hypotenuse

AC²=AB²+BC²

(60+BC)²=(30+BC)²+BC²

3600+BC²+120BC=900+BC²+60BC+BC²

On solving

BC²-60BC-2700=0

BC²-90BC+30BC-2700 =0

BC(BC-90)+30(BC-90)=0

BC=90m or - 30m(NA)

AB=120m

Answer 2

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Consider a Rectangle ABCD

Let the shorter be x

Diagonal= (60+x)

length= (x+30)

Now the diagonal BD is hypotenus

( BD )² = ( AB)² +( AD )²

(60+x)²= (x+30)² + x²

60² + x²+ 2× 60×x.

x²-60-2700=0

x²-90x+ 30x-2700

x(x-90) +30(x-90)

(x-90). (x+30)

x=90. x=-30

x(90+30)

x=120