Question

the diagonal of a rhombus are in the ratio 5 : 12.if its perimeter is 104cm.find the lengths of the side and the diagonals.

Answer 1

Answer:

The length of each side is 26 cm and the length of diagonals are 20 cm and 48 cm.

Step-by-step explanation:

Let the length of side of rhombus be x.

Its perimeter is 104 cm.

$x+x+x+x=104$

$4x=104$

$x=26$

Therefore the length of each side is 26 cm.

The diagonal of a rhombus are in the ratio 5 : 12. Let the length of diagonals are 5y and 12y. Diagonals are perpendicular bisector of each other.

Use Pythagoras in triangle AOB.

$AB^2=(AO)^2+(BO)^2$

$(26)^2=(2.5y)^2+(6y)^2$

$42.25 y^2 = 676$

$y^2=16$

$y=4$

The value of y is 4 cm. Therefore the length of diagonals are 20 cm and 48 cm.

Answer 2

Answer:

this is your answer

Step-by-step explanation:

hope it helps you

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