the diagonal of square 24 cm .find its area
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Answered by
0
Let the side of square =x
Then, by Pythagoras theorem,
x²+x²=24²
2x²=576
x²=576/2
x²=288. ----------1equation
Then,
Area of square =side²
Here, area of square =x²
Putting the value of x² from 1equation
Then,
Area of square =288cm²
I hope this will help you
-by ABHAY
Then, by Pythagoras theorem,
x²+x²=24²
2x²=576
x²=576/2
x²=288. ----------1equation
Then,
Area of square =side²
Here, area of square =x²
Putting the value of x² from 1equation
Then,
Area of square =288cm²
I hope this will help you
-by ABHAY
Answered by
0
diagonal 1=diagonal 2=24 cm
area =1/2×d1×d2
area=1/2×24×24 cm^2
area=288cm^2
area =1/2×d1×d2
area=1/2×24×24 cm^2
area=288cm^2
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