the diagonals ac and bd of a parrellogram ABC intersect at o. if oa is 2x - 3, oc is y+4, ob is x+3,and od is 2y-1, find values of x and y
Answers
Answered by
1
as the diagonals of parallelogram bisect each other then
OA=OC
OB=OD
SO
2X-3=Y+4. 2X=Y+1. 2X-Y=1
X+3=2Y+1. X+2=2Y. X-2Y= -2.
2X-Y=1
X-2Y= -2.
MULTIPLYING 2ND EQUATION WITH 2 WE GET
2X-Y=1
2X-4Y= -4
NOW SUBTRACTING BOTH THE EQUATIONS WE GET
3Y= 5
Y=3/5
OA=OC
OB=OD
SO
2X-3=Y+4. 2X=Y+1. 2X-Y=1
X+3=2Y+1. X+2=2Y. X-2Y= -2.
2X-Y=1
X-2Y= -2.
MULTIPLYING 2ND EQUATION WITH 2 WE GET
2X-Y=1
2X-4Y= -4
NOW SUBTRACTING BOTH THE EQUATIONS WE GET
3Y= 5
Y=3/5
Similar questions