The diagonals of a parallelogram ABCD intersect at O. If ∠BOC = 85° and ∠BDC = 65°, then ∠OAB
is :
A 10° B 20° C 40° D 95°
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Answered by
3
Step-by-step explanation:
it should be 30 degrees
85+65 = 150 and 180 - 150 is 30 degrees
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