Math, asked by madhurjyathegreat9, 1 year ago

The diagonals of a rhombus are 16 cm and 30 cm. Find the length of the side of the rhombus.

Answers

Answered by renukasingh05011979
3

Answer:

Perimeter of Rhombus :

Diagonals of perimeter are perpendicular to each other . So ,we can use Pythagorean theorem to find the side length of rhombus .

Diagonal = 16/2 = 8cm

Diagonal = 30/2 = 15cm

82+152 = s²

64+225 = 289 = s²

Side length(s) = 17

Perimeter of rhombus = 4 x 17 = 68 cm

I Hope It Will Help!

^_^


madhurjyathegreat9: How the ANSWER is 17
Strangercitizen1525: root of 289 is 17
madhurjyathegreat9: THANK YOU SO MUCH
renukasingh05011979: Thank you for marking me as brainliest!!!!
renukasingh05011979: ^_^
Answered by Strangercitizen1525
2

Answer:

length of the side of rhombus is 17cm.

Step-by-step explanation:

Let the diagonals are AC and BD Let

AC=16 cm BD=30 cm

AC and BD intersect at O

AO = OC = 16/2 = 8 cm

BO = OD = 30/2 = 15 cm

AOB is right angled triangle right angled at O

[in a rhombus diagonals bisect at

right angle]

AO^2 + BO^2 = AB^2

64 + 225 = AB^2

AB = (√289) = 17

The length of the side is 17 cm


madhurjyathegreat9: How ANSWER is 17
Strangercitizen1525: I hv explained the steps
Strangercitizen1525: root of 289 if 17
Strangercitizen1525: is*
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