Question

The sum of three consecutive multiples of 6 is 666

Answer 1

Let first multiple =6x acc to question 6x+6(x+1)+6(x+2)+6(x+ 3)=666 6x+6x+6+6x+12+6x+18=666

Answer 2

Here is your solution

Let,

The first multiple of 6 be x 

Second multiple = x+6 

Third multiple = x+6+6 = x+12 

A/q

x+x+6+x+12 = 666
=>3x + 18 = 666
=>3x = 666-18 = 648
=>x = 648/3 
=>x = 216 

Hence,
x=216
x+6 = 222
x+12 = 228 

So, the multiples are 216, 222 and 228.
 
Hope it helps you