the diagonals of a rhombus are in the ratio 5:12. if the perimeter is 104 cm find the length of the sides and the diagonals
Answers
Answered by
14
Sides = 1/4*104 = 26
Diagonals of rhombus bisector each other
= (5x/2)sq + (12x+2)sq = (26)sq
=25x.sq/4 + 144x.sq/4 = 676
= 169x.sq/4 = 676
=2704/169 = x. sq
16= x. sq
X = 4cm
Diagonals 5*4 = 20 cm
12*4=48 cm
Diagonals of rhombus bisector each other
= (5x/2)sq + (12x+2)sq = (26)sq
=25x.sq/4 + 144x.sq/4 = 676
= 169x.sq/4 = 676
=2704/169 = x. sq
16= x. sq
X = 4cm
Diagonals 5*4 = 20 cm
12*4=48 cm
Similar questions