The diameter and length of a roller are 70 cm and 100 cm respectively it moves once over to level a playground of area 4400 m square find the number of revolution the roller will take to level the playground.
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1 curved surface area of roller = 2pie*r*H
=2*22/7*35*100 =22000 cm.sq
=2.2m.sqarea of geround =4400m.sq
1 revolution cover =2.2 m.sq
how many revolution = 4400/2.2
= 2000 revolution
i hope its help you
mark brainliest
=2*22/7*35*100 =22000 cm.sq
=2.2m.sqarea of geround =4400m.sq
1 revolution cover =2.2 m.sq
how many revolution = 4400/2.2
= 2000 revolution
i hope its help you
mark brainliest
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