Question

The diameter of a 2.5 m long roller is 92 cm. If it takes 150 revolutions to level a playground, then find the

approximate cost of levelling the ground at the rate of 60 paise per square metre​

Answer 1

Step-by-step explanation:

it is cylinder

CSA=2pie *r*h=2*3.14*0.92*2.5=14.44m

when revolves 150 round

14.44*150=2166.6m

cost @60p

2166.6*60=129996=1299.96 rs

Answer 2

6505714.26 ruppees

Step-by-step explanation:

Diameter= 2.5m

length= 92cm,

1m=100cm

2.5m=250cm

let length be height

Radius=diameter÷2

Radius=250/÷2

Radius=125cm

area of curved surface =2πrh

2× 22÷7 ×125× 92=

506000/7=72285.714cm^2

it took 150 revolutions, So

72285.714× 150= 10842857.1cm

Cost of levelling the ground= 60 paise

10842857.1× 60= 650571426 paise

1 paise = 1÷100 ruppees

650571426÷100= 6505714.26 ruppees

So, our answer is = 6505714.26 ruppees