The diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are 14 cm and 38 cm respectively. If its height is 16 cm
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here,r1=14cm,r2=38cm,h=16cm,
volume of frustum=1/3×pi×(r1^2+r2^2+r1×r2)×h
=1/3×22/7×(14^2+38^2+14×38)×16
=22/21×(196+1444+532)×16
=22/21×2172×16
=22/7×724×16
=36,406.85
volume of frustum=1/3×pi×(r1^2+r2^2+r1×r2)×h
=1/3×22/7×(14^2+38^2+14×38)×16
=22/21×(196+1444+532)×16
=22/21×2172×16
=22/7×724×16
=36,406.85
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