Question

A man invest 1200 for 2 years at compound interest after one year the money amount to 1275 find the interest for 2nd year correct to the nearest rupee

Answer 1

Answer:I hope this helps.

Step-by-step explanation:

Answer 2

Answer:

Interest for 2nd Group is RS. 79.69

Step-by-step explanation:

Given: P = Rs. 1200

           T = 1 year

           A = Rs. 1275

To find: Interest of 2nd year

let R be the rate.

Compound interest for 1st Year = 1275 - 1200 = Rs. 75

according to the Question,

$\frac{PRT}{100}=75$

$\frac{R\times1200\times1}{100}=75$

$R=75\times\frac{1}{12}$

$R=6.25$  %

Now, Interest for 2nd Year =  $\frac{1275\times6.25\times1}{100}$

                                              =  $\frac{7968.75}{100}$

                                              =  $79.69$

Therefore, Interest for 2nd Group is RS. 79.69