The difference between a two digit no. and the number obtained by interchanging the digit is 36.What is the difference between the sum and the difference of the digits of the no. if the ratio between the sum of the digits of the no. is 1:2.?Can anyone explain it with full process
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Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Step-by-step explanation:
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