Math, asked by rajanklg159, 11 months ago

the difference between a two digit number and the number obtained by interchanging the position of its digits is 72 find the difference between the two digits of that number​

Answers

Answered by supriths4804
19

Answer:

8.

Step-by-step explanation:

Le the digits be x and y.

Given that,

10x+y-(10y+x)=72

10x+y-10y-x=72

9x-9y=72

9(x-y)=72

x-y=72/9

x-y=8.

HOPE THIS BRING A SMILE IN YOUR FACE

Answered by jivya678
0

Let the first number be 10x+y

The question is asking the difference between the two digits which is x-y

GIVEN:

On interchanging the position of digits the difference between them becomes 72 which means :

10x+y-(10y-x)=72

which is equal to 9x-9y=72

We know,

9x-9y=72 which is equal to 9(x-y)=72

This implies x-y=8

X-Y=8

The difference between the two digits of the number is 8

#SPJ2

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