The difference between the compound interest and the simple interest on a certain sum of money at 15% per annum for three years is ₹283.50.find the sum.
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Heya friend,
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Let the sum be ₹P. Then,
S.I. = P×R×T/100
= P×15×3/100
=₹ 9P/20
C.I. = P{(1+R/100)^n - 1}
= P{(1+15/100)^3 - 1}
= P{(100+15/100)^3 - 1}
= P{(115/100)^3 - 1}
= P{(23/20)^3 - 1}
= P{12,167/8,000 - 1}
= P{12,167 - 8,000/8,000}
= ₹ 4,167P/8,000
Difference = C.I. - S.I.
=> 283.50 = 4,167P/8,000 - 9P/20
=> 28,350/100 = 4,167P - 3,600P/8,000
=> 567/2 = 567P/8,000
=> P = 8,000×567/567×2
=> P = ₹4,000
Hence, the sum is ₹ 4,000.
Thanks
With regards@
Tanisha
------------------------------------------------------------
Let the sum be ₹P. Then,
S.I. = P×R×T/100
= P×15×3/100
=₹ 9P/20
C.I. = P{(1+R/100)^n - 1}
= P{(1+15/100)^3 - 1}
= P{(100+15/100)^3 - 1}
= P{(115/100)^3 - 1}
= P{(23/20)^3 - 1}
= P{12,167/8,000 - 1}
= P{12,167 - 8,000/8,000}
= ₹ 4,167P/8,000
Difference = C.I. - S.I.
=> 283.50 = 4,167P/8,000 - 9P/20
=> 28,350/100 = 4,167P - 3,600P/8,000
=> 567/2 = 567P/8,000
=> P = 8,000×567/567×2
=> P = ₹4,000
Hence, the sum is ₹ 4,000.
Thanks
With regards@
Tanisha
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