the difference between the outer lateral surface area and inner lateral surface area of a cylindrical metal pipe 28 cm long is 176 cm find the outer and the inner radius of the pipe is made of 352 cm of metal
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Let the outer radius be 'R' and the inner radius be 'r'. By using the formula 2×pi×h (R-r)=176 we will get that (R-r)=1
Now by using pi×h×(R^2-r^2)=352 we will get that (R+r)=4
using (R-r)=1
R=1+r
In (R+r)=1+r+r=4
r=1.5
R=2.5
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