Math, asked by hariharii2006, 8 months ago

The difference between the two adjoining sides containing right angle of a right-angled
triangle is 14 cm. The area of triangle is 120 cm2
. Verify this area by using Heron’s formula

Answers

Answered by ayushyadav143
6

YOUR ANSWER IN THE FOLLOWING STEPS-:::::

Let the perpendicular be a cm

Base = a+14 cm

According to question

Area = 120

1/2 b *p =120

a(a+14) = 240

a^2 +14a-240 = 0

a^2 +24a - 10a - 240=0

a(a+24) - 10(a+24)= 0

(a+24)(a-10)=0

a= - 24 and a=10

Neglecting negative value, we get

a=10

Perpendicular = 10 cm

Base = 24 cm

Hypotenuse = 25 cm

Now,

semi perimeter = 59/2

(s-a) = 39/2

(s-b) = 11/2

(s-c) = 9/2

Area of triangle = root( 59*39*11*9/16)

= 3/4 * root 59*39*11

= 3/4 * 160(approx.)

= 3*40

=120 cm sq.

Answered by vishalkhandelwal5165
1

Answer:

Let the perpendicular be a cm

Base = a+14 cm

According to question

Area = 120

1/2 b *p =120

a(a+14) = 240

a^2 +14a-240 = 0

a^2 +24a - 10a - 240=0

a(a+24) - 10(a+24)= 0

(a+24)(a-10)=0

a= - 24 and a=10

Neglecting negative value, we get

a=10

Perpendicular = 10 cm

Base = 24 cm

Hypotenuse = 25 cm

Now,

semi perimeter = 59/2

(s-a) = 39/2

(s-b) = 11/2

(s-c) = 9/2

Area of triangle = root( 59*39*11*9/16)

= 3/4 * root 59*39*11

= 3/4 * 160(approx.)

= 3*40

=120 cm sq.

Similar questions