Math, asked by princegaate5603, 1 year ago

The difference in the simple interest and compound interest on principal of rs 10,00,000 in 3 yrs at 4% annum is

Answers

Answered by bedabrata85
0

SOLUTION

Let us find the S.I. And C.I separately

  1. SIMPLE INTEREST

 \frac{pnr}{100}  \\   =  \frac{1000000 \times 3  \times  12 \times 4 }{100}  \\  = rs.(1440000 - 1000000) = rs.440000

2.COMPOUND INTEREST

p(1 +  \frac{r}{100}) ^{n}   \\  = 1000000 \times  {( \frac{104}{100} )}^{3} \\  =rs. 1124864

Difference,

1124864 - 440000 = rs.684864

Answered by rishika79
0

Answer:

Step-by-step explanation:

principle = (interest x 100) / (time x rate)

= Rs. (100 x 80)/(4 x 2) = Rs. 1000

∴ C.I. =Rs.[{1000 x (1 + 4/100)2 - 1000}]

= Rs. 81.60

Hope it helps you...

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