The difference of a two digit number is 5, also the number obtained by reversing the digits is 9 less than three times of the original number. find the number
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Let us assume, x and y are the two digits of the two-digit number and let us assume, y > x
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
y - x = 5 ------------1
Also given:
10y + x = 3 (10x + y) - 9
10y + x = 30x + 3y - 9
29x - 7y = 9 -------------------2
Multiply equation 1 by 7
7y - 7x = 35 -------------3
adding equation 2 and equation 3
22x = 44
x = 2
Therefore, y = 5 + x = 5 + 2 = 7
Therefore, the two-digit number = 10x + y = 10*2 + 7 = 27
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
y - x = 5 ------------1
Also given:
10y + x = 3 (10x + y) - 9
10y + x = 30x + 3y - 9
29x - 7y = 9 -------------------2
Multiply equation 1 by 7
7y - 7x = 35 -------------3
adding equation 2 and equation 3
22x = 44
x = 2
Therefore, y = 5 + x = 5 + 2 = 7
Therefore, the two-digit number = 10x + y = 10*2 + 7 = 27
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