The difference of compound and simple interest on a certain sum of money is Rs121 at 11% pa compounded annually for 2 years .Find the principal.
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Answered by
0
Answer:
Let sum of money be
′
P
′
.
r=15%
T=2
S.I=
100
PTR
⇒S.I=
100
P×2×15
C.I=P(1+
100
R
)
T
−P
=P(1+
100
15
)
2
−P
=P(
20
23
)
2
−P
=
400
129P
ATP,
400
129P
−
10
3P
=117
⇒
400
129P−120P
=117
⇒9P=117×400
⇒P=
9
117×400
=5200
The principal is Rs 2500.
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Answered by
0
principal (p) =rs 121
time period =2yrs
rate of interest=11%
Di difference between C.I and S.I is given by the formula
C.I -A.I. =P(R/100)
=121( 2/100)
=2.02
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