The difference of two number is 11 & 1/5th of their sum is 9,the numbers are
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Answer:
let first number is X and second number is Y
x-y=11 (1) as per first condition
1/5(x+y)= 9 (2) as per second given conditions
X + Y = 45 (2)
X - Y = 11 (1) by adding both equations
2x=56
x=28
y=17
Answered by
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Your answer is :-
let the number be X and Y
•°• according to question
1/5(X+Y) = 9 => X+Y = 45 .....(1)
X-Y = 11 ....(2) [ condition X>Y]
solving (1) and (2) , we get
2X = 56
=> X = 28
=> Y = 17
let the number be X and Y
•°• according to question
1/5(X+Y) = 9 => X+Y = 45 .....(1)
X-Y = 11 ....(2) [ condition X>Y]
solving (1) and (2) , we get
2X = 56
=> X = 28
=> Y = 17
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