Question

The difference of two numbers is 13 and 1/5th of their sum is 9. Find the greater number.​

Answer 1

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Let the 2 numbers be x and y

x-y = 11. (1)

1/5(x+y) = 9.

Thus, x+y = 9*5 = 45. (2)

x = y+11 ( from eqn. 1). (3)

Substituting to eqn. 2

y+y+11 = 45

2y = 45–11 = 34

y = 34/2 = 17

Now, x-y = 11

x-17 =11

x = 17+11

x = 28

Thus, the numbers are,

x =28

y =17

Answer 2

Answer

y=16

and

x=29

Step-by-step explanation:

1) x+y    =45

  29+16=45

  45     =45

2) x-y    =13

   29-16=13

   13      =13