Question

The difference or two acute angles of a right-angle triangle is 2÷5×π radian. Find the measure of the acute angles in radian and degree.​

Answer 1

Answer:

therfore,2pi/5 x 180/pi = 72 degree.

Step-by-step explanation:

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Answer 2

Answer:

Given as the difference between the two acute angles of a right-angled triangle is 2π/5 radians.

As we know that π rad = 180° ⇒ 1 rad = 180°/π

Also given

2π/5

(2π/5 × 180/ π)°

By substituting the value of π = 22/7

(2 × 22/(7 × 5) × 180/22 × 7)

(2/5 × 180)°

72°

Suppose one acute angle be x° and the other acute angle be 90° – x°.

Now,

x° – (90° – x°) = 72°

2x° – 90° = 72°

2x° = 72° + 90°

2x° = 162°

x° = 162°/2

x° = 81° and

90° – x° = 90° – 81°

= 9°

Thus, the angles are 81° and 9°

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