the digit at ten place of a two digit number is four times the digit at units place.if the sum of this number and the number formed by reversing the digit is 55.find the number.i can't answer anyone because I have no point
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Step-by-step explanation:
Let the two digit number be 10 x + y . The number formed on reversing the digits is 10 y + x . The original number is 10 ( 4 ) + 1 = 40 + 1 = 41 .
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