The digit at the tens place of a two digit number is 4 times the digit at ones place if the sum of this number and the number formed by reversing the digit is 55 find the number
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Step-by-step explanation:
this is your answer
the digit is 41
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Step-by-step explanation:
let the digit of ones place be x
Then,digit of tens place = 4x
Number formed = 40x + x=41x
After reversing the number formed=10x+4x=14x
As per question
41x+14x=55
55x =55
x=55÷55
x=1
Then the number = 41
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