The digits of a positive integer 'n' are four consecutive integers in decreasing order when read from left to right. What is the sum of the possible remainders when 'n' is divided by 41 ?
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➺ The digits of a positive integer n are four consecutive integers in decreasing order when read from left to right.
The possible number can be ; 9876, 8765, 7654, 6543, 5432, 4321, 3210.
Hence, the sum of possible remainders is ‘217’
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your answer is 237
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