Question

The digits of a two digit number different by 3.if the digits are inter changed , and the resulting number is added to the original number, we get 143.what can be the original number?​

Answer 1

Answer:

Original number is 58

Step-by-step explanation:

let

Unit place digit be X

Then ten's place digit is X-3

Number= (X-3) 10 + X

If digits are reversed

Number is 10x + X-3

Given

(X-3) 10+X + 10X + X-3 = 143

10X-30+X+10X+X-3 = 143

22X-33= 143

22X = 176

X = 176/22

X= 8

so the original number is 58

Answer 2

Answer:

Let us assume, the X is the tenth place digit and y is the unit place digit of the two digit number Also assume that x>y

Therfore the 2 digit number is 10x+y and reversed number is 10y+c

Given

X-y =3......(.1)

ALSO given

10x +y +10y+x=143

11x+11y =143

X+y= 13.....(2)

Adding equation 1 and 2

2x=16

X=8

Therfore y= x-3= 8-3 =5

Therfore the 2 digit number = 10x+y

=10*8+5=85

HOPE IT HELPS YOU