The digits of the two digit number differ by 5 if the digits are interchanged and resulting number is added to the number 99 find the original number.
Can anyone please give me an easy method to solve this question, please give me an method according to the level of class 8th.
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Answered by
0
Answer:
IAM in class 7
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Answered by
1
Answer:
Let the one digit number be x
And tens digit number be y
(y>x)
No. 10y+x
And interchanged no. =10x+y
According to the question,
x-y=5.............¡
10y+x+10x+y=99
=>11y+11x=99
=>x+y=9..........¡¡
Now ¡¡-¡ we get,
x+y-(x-y) =9-5
=>2y=4
=>y=2
Putting y=2in equation ¡
x-y=5
=>x-2=5
=>x=7
The number is
10y+x=10×2+7=27
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