the dimension of a cuboid are 1 m by 80 cm by 64 cm. it is melted and cast into a cube. find the surface area of the cube.
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Answered by
3
Dimensions of cuboid=100*80*64 cm
Vol. of cuboid =100*80*64 cm cube
Vol. Of cuboid =vol. Of cube
100*80*64=(side)3
Side of cube=8
CSA of cube=6(side)2
=6(8*8)=384 m cube
Vol. of cuboid =100*80*64 cm cube
Vol. Of cuboid =vol. Of cube
100*80*64=(side)3
Side of cube=8
CSA of cube=6(side)2
=6(8*8)=384 m cube
nitthesh7:
sry its 80 cm as 512000 cube root is 80 and not 8
oh
also csa not equal to 6a^2 tsa = 6a^2
Answered by
12
Volume of cuboid = lbh
= 100 × 80 × 64
= 512000 cm³
As it is melted
Then, Volume of cube = Volume of cuboid
a³ = 512000
a = ∛512000
a = 80 cm
Surface area of cube = 6a²
= 6 × 80 × 80
= 38400 cm²
:) Hope this helps!!!
= 100 × 80 × 64
= 512000 cm³
As it is melted
Then, Volume of cube = Volume of cuboid
a³ = 512000
a = ∛512000
a = 80 cm
Surface area of cube = 6a²
= 6 × 80 × 80
= 38400 cm²
:) Hope this helps!!!
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