Physics, asked by kashish5362, 11 months ago

The dimensional formula of integrated tdt is​

Answers

Answered by kartikthakran14
7

Answer:

The point is that the dimensional analysis will break down unless −αx2 is just a number (and so e−αx2 is too), so α must have the dimensions of x−2.

It then does not matter what value α then takes, so long as it has those dimensions.

In some cases this might be hidden, for example where the exponent uses a unit like radians or decibels, but in those cases the unit is essentially a ratio or a function of a ratio and so is still effectively dimensionless.

Thanks they thiyo bhai

Answered by shradhaverma85
3

THE DIMENSIONAL FORMULA OF intregation tdt is

(M^ 0 L ^0 T^ 2).

may it help u

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