The dimensional formula of integrated tdt is
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The point is that the dimensional analysis will break down unless −αx2 is just a number (and so e−αx2 is too), so α must have the dimensions of x−2.
It then does not matter what value α then takes, so long as it has those dimensions.
In some cases this might be hidden, for example where the exponent uses a unit like radians or decibels, but in those cases the unit is essentially a ratio or a function of a ratio and so is still effectively dimensionless.
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THE DIMENSIONAL FORMULA OF intregation tdt is
(M^ 0 L ^0 T^ 2).
may it help u
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