Question

The dimensions of a block is 100 mx 1 mx 1 m. The specific resistance of the material of the block is 4x10-6 Ω-m. Calculate its resistance across its square faces.​

Answer 1

Explanation:

Dimensions of block = 100m × 1m × 1m

Length (l) = 100 m

Area (a) = 1 m²

Specific Resistance (p)= 4 × 10-⁶ Ω-m

Resistance = ?

$Resistance \: = p \times \frac{l}{a}$

$Resistance \: = 4 \times {10}^{ - 6} \times \frac{100}{1}$

$Resistance \: = 4 \times {10}^{ - 4} Ω$

Answer 2

Answer:

l=100m

A=l∗b=1m^2

putting values

R=4∗10^−6Ω-m

R=pl/A

4*10^-6Ω-m*100m/1m^2

so answer is

R= 4*10^-4Ω

Explanation:

here two 'm' in numerator will cancel out m^2 in denominator