Question

the dimensions of a metallic cuboid are 44 cm *42 cm*21 cm. It is melted and cast into a sphere. what is the radius of this sphere?

Answer 1

hello friend

here is your answer

volume before melting =volume after melting
volume of cuboid = volume of sphere
l×b×h= 4/3πr^3
44×42×21= 4/3πr^3
44×42×21×3/4×7/22=r^3
21×21×3×7=r^3
9261=r^3
21= r

the radius of sphere is 21


thanks dear

Answer 2

The radius of sphere is 21.

Step-by-step explanation:

Given : The dimensions of a metallic cuboid are 44 cm *42 cm*21 cm. It is melted and cast into a sphere.

To find : What is the radius of this sphere?

Solution :

Volume of cuboid is $V=l\times b\times h$

Volume of sphere is $V=\frac{4}{3}\pi r^3$

As cuboid is melted and cast into a sphere.

So, Volume of cuboid = Volume of sphere

i.e. $l\times b\times h=\frac{4}{3}\pi r^3$

Substitute the values,

$44\times 42\times 21=\frac{4}{3}\times \frac{22}{7}\times r^3$

$r^3=\frac{44\times 42\times 21\times 3\times 7}{4\times 22}$

$r^3=9261$

$r=\sqrt[3]{9261}$

$r=21$

Therefore, the radius of sphere is 21.

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