Physics, asked by shivamtuli1526, 1 year ago

The dimensions of permittivity [ε₀] are ______ .Take Q as the dimension of charge.(A) M¹ L⁻² T⁻² Q⁻²
(B) M⁻¹ L² T⁻³ Q⁻¹
(C) M⁻¹ L⁻³ T² Q²
(D) M⁻¹ L³ T⁻² Q⁻²

Answers

Answered by Arslankincsem
5

The dimensions of permittivity [ε₀] are M⁻¹ L⁻³ T² Q².


Take Q as the dimension of charge.


The dimensions of are. L 2 = M − 1 L − 3 T 4 A 2, where M, L , T and are the dimensions of mass, length, time as well as current respectively.

Answered by Anonymous
4
Holla ^_^


☸ Required Answer is ⬇ ⬇⬇ ⬇


⭕ (C) M⁻¹ L⁻³ T² Q²



Vielen Dank ♥
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