Question

the dipole moment of HX molecule is 1.92D and bond distance ia 1.2A°.what is the percentage ionic character of HX

Answer 1

Dipole moment (theoretical) μ = Q x d coulomb-metre

Q is the charge of electron = 1.6 x 10^-19 C

d is the bond length in metres

μ = 1.6 x 10^-19 x 1.2 x 10^-10 = 1.92 x 10^-29 C-m = 19.2 x 10^-30 C-m

= 5.75 D

(1 debye = 3.34 x 10^-30 C-m)

% ionic character = actual dipole x 100/ theortical dipole

= 1.92 x 100/ 5.75 = 33.4 %

Answer 2

Explanation:

hope it helps you........