Question

the dipole moment of LiH is 1.964×10*-29 cm and the inter atomic distance between Li and H in this molecule is 1.596A°. What is the percent ionic character in LiH​

Answer 1

Explanation:

ANSWER

The practical dipole moment= 1.964×10

−29

cm

Theoretical dipole moment= = (1 electronic charge) × (interatomic distance)

= 1.602×10

−19

×1.596×10

−10

=2.557×10

−29

cm

Now the fraction of practical to theoretical dipole moment will give us the value of percentage ionic character in LiH

=

2.557×10

−29

1.964×10

−29

=0.768 or 76.8%

Answer 2

Answer:

ANSWER

The practical dipole moment= 1.964×10

−29

cm

Theoretical dipole moment= = (1 electronic charge) × (interatomic distance)

= 1.602×10

−19

×1.596×10

−10

=2.557×10

−29

cm

Now the fraction of practical to theoretical dipole moment will give us the value of percentage ionic character in LiH

=

2.557×10

−29

1.964×10

−29

=0.768 or 76.8%

Explanation:

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