Question

The displacement of a moving particle is given by,
x = at^3+ bt^2+ ct + d. The acceleration of particle
at t = 3 s would be
​

Answer 1

v=X/t=3at^2+2bt+c

a=v/t=6at+2b

at t=3s

a=18a+2b

hope this helps u

Answer 2

KINEMATICS AS APPROACH OF DERIVATiVES

Here , we know that ,

X = displacemnt = at^3+ bt^2 + ct +d

so the velocity of the particke will be as ,

dX/dt = V = 3at^2 + 2bt + c

now , we also know that ,

Acceleration of the particle is given as derivative of the velocity, so we get as ,

dV/dt = 6at + 2b

now acceleration at , t= 3 , will be as

Dv/Dt = A = 18a + 2b m/s^2