the displacement of a particle makes an angle with the force acting on it for which value of E is the work done maximum for which value of E is the work done minimum
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As work=F×S cos theta [work is scalar product of two vectors force and displacement]
Max. Value of cos theta =1 which occurs when theta =0° i.e the force and displacement is parallel and in same direction.
Min. Value of cos theta=-1 which occurs when theta =180° i.e the force and displacement is anti-parallel and in opposite directions.
Max. Value of cos theta =1 which occurs when theta =0° i.e the force and displacement is parallel and in same direction.
Min. Value of cos theta=-1 which occurs when theta =180° i.e the force and displacement is anti-parallel and in opposite directions.
sneha279:
can u explain in simple way
according to 9 clasa
According to 9 class when angle is 0° work is max. And when angle is 180° work is min.
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According to 9 class when angle is 0° work is max. And when angle is 180° work is min.
As work=F×S cos theta [work is scalar product of two vectors force and displacement]
Max. Value of cos theta =1 which occurs when theta =0° i.e the force and displacement is parallel and in same direction.
Min. Value of cos theta=-1 which occurs when theta =180° i.e the force and displacement is anti-parallel and in opposite directions.
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