Question

The displacement of a particle moving in x direction is x=18t+5t2. calculate average velocity between 2 second and 3 second

Answer 1

x = 18t + 5t^2.

as v = dx/dt

so, v = 18 + 10t

for t = 2 s

v = 18 + 10*2 = 38 m/s

for t = 3s

v = 18 + 10*3 = 48 m/s

avg. velocity between 2s andd 3s

= (48+38)/2

= 86/2 = 43 m/s

Answer 2

here is d answer........