Chemistry, asked by lakshmiprasanna8041, 8 months ago

The dissociation constant of acetic acid of given temperature is 1.69 \times 10^{-5} .1.69×10 −5 . The degree of dissociation of 0.01M acetic acid in the presence of 0.01M H C lHCl is equal to

Answers

Answered by dharamrajktr6
1

Answer:

1.69×10^-3

here's the answer and hope this helps you.

Attachments:
Similar questions