Question

The distance between ( cos$ , sin$) and ( sin$, -cos$) is ​

Answer 1

Answer:

√2

Step-by-step explanation:

Distance b/w these two points is

√[(sin$-cos$)^2 + (-cos$-sin$)^2]

= (sin^2$ + cos^2$) - 2sin$cos$ + (cos^2$ + sin^2$) + 2cos$sin$

= √(1+1)

= √2

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