Question

the distance between madras and Bangalore is 360km/h bus A starts from madras at a constant speed of 40km/h at a same time bus B starts from bangalore 50km/h and meet enroute how much distance had bus A travelled from the madras when they meet ??​

Answer 1

||✪✪ QUESTION ✪✪||

the distance between madras and Bangalore is 360km/h bus A starts from madras at a constant speed of 40km/h at a same time bus B starts from bangalore 50km/h and meet enroute how much distance had bus A travelled from the madras when they meet ??

|| ✰✰ ANSWER ✰✰ ||

Given That, Total Distance b/w Bangalore and Madras is 360km .

And, bus A starts from madras at a constant speed of 40km/h at a same time bus B starts from bangalore 50km/h ..

Since Both The bus are Travelling in Opposite Directions ,

So, we can say That,

→ usual speed = (40 + 50) = 90km/h.

Now,

→ Distance = 360km

So,

→ Time They will take in Meeting Each other = (Total distance) / ( usual Speed).

→ Time = (360)/(90) = 4 Hours.

So, They Meet After 4 hours.

Now , Bus A starts From Madras as a constant Speed of 40km/h. And Now, we know That, They meet after 4 hours.

So,

→ Distance Cover By bus A = Speed * Time

→ Distance = 40 * 4 = 160km .

Hence, Bus A covers 160km Distance Before Meeting to Bus B.

Answer 2

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In, the image let bus A start from Madras and Bus B from Bangalore at the same time & they meet at point P

Let distance of point

 P from Madras     =      x  km

Then, distance of point

P from Bangalore    = 360 -  x  km

Speed of Bus A (given) = 40km/h

Speed of bus B (given) = 50 km)/h

Bus A and B will meet at Point P after travelling for equal durations

HENCE,

time taken by Bus A to reach point P will be equal to the time taken by Bus B to reach point P

So,

(using formula ; time= distance/speed)

x/40 = (360-x) / 50

(Cross multiplying we will get)

50x = 14400 - 40x

50x + 40x = 14400

90x = 14400

x= 160

HENCE, DISTANCE TRAVELLED BY BUS A FROM MADRAS WILL BE 160 km.

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