Question

The distance between the points (7, 4) and (-1, 8) is..... Units

Answer 1

HeYa❤️...

Answer:

$distance \: formula = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

$= \sqrt{( - 1 - 7) {}^{2} + (8 - 4) {}^{2} } \\ \\ = \sqrt{( - 8) {}^{2} + (4) {}^{2} } \\ \\ = \sqrt{64 + 16} \\ \\ = \sqrt{80}$

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Answer 2

Answer:

The distance between the points  (7, 4) and (-1, 8) = 4√5 units

Step-by-step explanation:

To find,

The distance between the points  (7, 4) and (-1, 8)

Solution:

Recall the concept:

Distance formula:

The distance between the points (x₁,y₁) and (x₂,y₂) is given by

$\sqrt{(x_2 - x_1) ^2 + (y_2- y_1)^2}$

Here we have,

x₁ = 7

y₁ = 4

x₂ = -1

y₂ = 8

The distance between the points  (7, 4) and (-1, 8) = $\sqrt{(-1-7) ^2 + (8- 4)^2}$

= $\sqrt{(-8) ^2 + (4)^2}$

= $\sqrt{64+ 16}$

= $\sqrt{80}$

= 4√5

The distance between the points  (7, 4) and (-1, 8) = 4√5 units

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