Physics, asked by 552330302, 1 year ago

The distance by a body falling freely from the rest in 2nd,3rd and 5th second its motion are in the ratio
a) 7:5:3
b) 3:5:7
c) 5:3:7
d) 5:7:3

Answers

Answered by TrapNation
1
» We know that
St = u + 1/2a ( 2t-t)

where t = 2,3,5 and u = 0

S2 = 1/2×10(4-1) = 15

S3 = 1/2×10(6-1) = 25

S5 = 1/2×10(10-1) = 45

Therefore, S2:S3:S5 = 3:5:9

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