Question

The distance of the eye-lens from the retina is x. For a normal eye, the maximum focal length of the eye-lens
(a) = x
(b) < x
(c) > x
(d) = 2 x

Answer 1

Answer:

C. >x

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Answer 2

The maximum focal length of the eye-lens     f = x.

Option (a) f = x.

Explanation:

For normal vision / eye,

We have :

Far point where you can position the object , u = ∞

Distance between the retina and the eye lens : v = x

Therefore, we have :

$\begin{equation}\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\end$

$\begin{equation}\frac{1}{f}=\frac{1}{x}-\frac{1}{\infty}\end$

$\frac{1}{\infty}\end$ ,is neglected because of one divide by large quantity.

So ,

$\begin{equation}\frac{1}{f}=\frac{1}{x}\end$

Reciprocal both side  

That is,  

f = x

Thus, the maximum eye-lens focal length is f = x.