Chemistry, asked by Piyushjain2668, 9 months ago

Cu⁺ (aq) is unstable in solution and undergoes
simultaneous oxidation and reduction according to the
reaction :
2Cu⁺ (aq) ⇋ Cu²⁺ (aq) + Cu(s) choose correct Eº for
given reaction if Eº Cu²⁺/Cu = 0.34 V and Eº Cu²⁺/Cu⁺ = 0.15
V
(a) –0.38 V (b) +0.49 V
(c) +0.38 V (d) –0.19 V

Answers

Answered by skyadav14
1

Explanation:

ANSWER

From given data (from ΔG

o

=−nE

o

F)

(i)Cu(s)⟶Cu

2+

(aq)+2e

. ΔG

1

o

=−2×(−0.34)×F

(ii)Cu

2+

(aq)+e

⟶Cu

+

(aq). ΔG

2

o

=−1×(0.15)F

On adition

Cu(s)⟶Cu

+

(aq)+e

. ΔG

3

o

=−1×E

o

×E

ΔG

3

o

=ΔG

1

o

+ΔG

2

o

=(−2×−0.34×F)+(−1×0.15×F)

=+0.68F−0.15F−0.53F

or E

o

=−0.53V

Reaction,

$$2{Cu}^{+}(aq)\rightleftharpoons {Cu}^{2+}(aq)+Cu(s){E}^{o}=?$$

So, Cu

+

(aq)+e

⇌Cu(s), E

o

=+0.53V

$${Cu}^{+}(aq)\rightleftharpoons {Cu}^{2+}(aq)+{e}^{-}$$; E

o

=−0.15V

$$3{Cu}^{+}(aq)\rightleftharpoons {Cu}^{2+}(aq)+Cu(s)$$, E

o

=+0.38V

Similar questions