Question

If the following half cells have E° values as
A³⁺ + e⁻ → A²⁺, E° = y₂V
A²⁺ + 2e⁻ → A, E° = –y₁V
The E° of the half cell A³⁺ + 3e → A will be
(a) 2y₁ - y₂/3
(b) y₂ - 2y₁/3
(c) 2y₁ – 3y₂ (d) y₂ – 2y₁

Answer 1

The Eo of the half cell will be 0.04 V

Option (C) is correct.

Explanation:

Correct statement:

If the following half cells have the E° values as  

Fe+3 + e– → Fe+2 ; E° = + 0.77 V and

Fe+2 + 2e– → Fe ; E° = – 0.44 V. The E° of the half cell Fe+3 + 3e– → Fe will be:     (a) 0.33 V         (b) 1.21 V          (c) 0.04 V        (d) 0.605 V

Solution:

The solution is as follows:

Fe3+ + e− → Fe2+     ΔG1 = FE1+

Fe2+ + 2 e− → Fe     ΔG2 = 2FE2

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Fe3+ + 3 e− → Fe   ΔG3 = Δ G1 + Δ G2

3 FE3 = FE1 + 2FE2    

3  E3 = E1 + 2 E  

E3 = 0.77 + 2 (−0.44) 3 = 0.04 V

Thus the Eo of the half cell will be 0.04 V

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