Question

The distance of the point p(-3,-4) from the x axis is

Answer 1

Answer:

The distance of the point P(-3,-4) from the x-axis = |-4| = 4 units. 2. The distance of the point P(-3,-4) from the y-axis is = |-3| = 3 units. Therefore, the required answer is 4 units.

Answer 2

Step-by-step explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

$\huge\bold{GIVEN:-} \\ \\ P = ( -3, -4) \\ O = (0, 0)$

$\\ \\ \huge\red{formula:-} \\ \\ Distance = \sqrt{{(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2}}$

$\implies D = \sqrt{{(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2}} \\ \\ D = \sqrt{{(-3 - 0)}^{2} + {(-4 - 0)}^{2}} \\ \\ D = \sqrt{9 + 16} \\ \\ D = \sqrt{25} \\ \\ \huge\boxed{ D = 5 \: units}$

# BAL

# Answer with quality..