Question

the distance travelled by a body falling freely from rest in first second and third second are in ratio of :

Answer 1

distance travelled by a body in nth second is given by  Sn=u+a/2(2n-1).(n- nth second)
here u=0
 S1=0+a/2(2*1-1)
S1=a/2
S2=0+a/2(2*2-1)
a/2(3)
S2=3a/2
similarly S3=a/2(2*3-1)
S3=5a/2
So S1:S2:S3=1:3:5

Answer 2

A body falling freely from a height towards the earth, moves with uniform  

(1) Speed  

(2) Velocity  

(3) Acceleration  

(4) Weight