The distance travelled by a freely falling body is proportional to
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Distance travelled by freely falling body is H=1/2gt^2. So it is directly proportional to t^2
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Answer:
the square of time for which it falls
Explanation:
From the equations of motion
s=ut+ 1/2at^2
INITIAL VELOCITY OF FREEFALL= 0
ASSUME a=g
s=ut+1/2gt^2
s=(0)t+1/2gt^2
s=1/2gt^2
From the above equation it is clear that distance travelled is directly proportional to t^2
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