Physics, asked by Mousin636, 1 year ago

The distance travelled by a freely falling body is proportional to

Answers

Answered by bhavasagar
16
Distance travelled by freely falling body is H=1/2gt^2. So it is directly proportional to t^2
Answered by Player71
4

Answer:

the square of time for which it falls

Explanation:

From the equations of motion

s=ut+  1/2at^2

INITIAL VELOCITY OF FREEFALL= 0

ASSUME   a=g

s=ut+1/2gt^2

s=(0)t+1/2gt^2

 s=1/2gt^2

 

From the above equation it is clear that distance travelled is directly proportional to t^2

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